d若函数的解析式、值域相同,定义域不同,则称这些函数为“孪生函数”

2个回答

  • 解析式为y=2X^2+1,值域为{5,19,1}的定义域可以是{0,√2,3}或{0,√2,-3}或{0,-√2,3}或{0,-√2,-3}或{0,-√2,√2,3}或{0,-√2,√2,-3}或{0,√2,3,-3}或{0,-√2,3,-3}或{0,√2,-√2,3,-3},故解析式为y=2X^2+1,值域为{5,19,1}的“孪生函数”共有9个.