已知下列条件求圆的方程1.圆心在y轴上,半径是5,经过点(-3,2)2.经过(-1,1)(4,1)(-1,4)3.经过原

3个回答

  • 1.设圆心C(0,b),圆的方程为x² + (y-b)² = 25

    代入(-3,2):9 + (2-b)² = 25

    b = 6或b = -2

    圆的方程为x² + (y -6)² = 25或x² + (y+2)² = 25

    2.设圆心(a,b),半径r

    (x-a)² + (y-b)² = r²

    代入3点的坐标:

    (a+1)² + (b-1)² = r² (1)

    (a-4)² + (b-1)² = r² (2)

    (a+1)² + (b-4)² = r² (3)

    由(1)(2): (a+1)² = (a-4)²

    a + 1 = a - 4 (无解)

    或a+1 = 4-a,a = 3/2

    类似,由(1)(3),b = 5/2

    r² = 17/2

    (x - 3/2)² + (y - 5/2)² = 17/2

    3.原点和A(1,1)的中点为B(1/2,1/2),OA的斜率为(1-0)/(1-0) = 1

    OA的中垂线的斜率为-1,方程为y - 1/2 = -(x - 1/2),y = 1 -x

    与2x + 3y + 1 = 0联立,可得圆心为C(4,-3)

    半径=OC=√(4-0)²+(-3-0)² = 5

    圆的方程:(x-4)² + (y+3)² = 25