(1)g(x)=5x+c是奇函数,c=0,g(x)=5xa1=1f(an+a(n+1))-g(a(n+1)*an+an^2)=13(an+a(n+1))^2+1-5(a(n+1)*an+an^2)=1化简得(a(n+1)+an)(3a(n+1)-2an)=0由an>0即3a(n+1)-2an=0a(n+1)=2an/3an=(2/3)^(n-1)(2)Sn=3-3*(2/3)^n...
已知函数f(x)=3x的2次方+1是偶函数,g(x)=5x+c是奇函数,数列{an}满足an>0且a1=1,f(an+a
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