∵AB∥CD
∴∠BEF+∠DFE=180°
∵PE平分∠BEF,PF平分∠DFE
∴∠PEF=1/2∠BEF,∠PFE=1/2∠DFE
∴∠PEF+∠PFE=1/2×180°=90°
∴∠P=90°
问一道初一的题,讲清楚就好）图的字有些小,不要介意.
∵AB∥CD
∴∠BEF+∠DFE=180°
∵PE平分∠BEF,PF平分∠DFE
∴∠PEF=1/2∠BEF,∠PFE=1/2∠DFE
∴∠PEF+∠PFE=1/2×180°=90°
∴∠P=90°