Question

计算:(2000^2+1998)(1997^2-1997)/(1998^2-2000)(1998*2001-4)

Answer 1

设x=1998,则

原式=[(x+2)^+x][(x-1)^-(x-1)]/{(x^-x-2)[x(x+3)-4]}

=(x^+5x+4)(x-1)(x-2)/[(x+1)(x-2)(x-1)(x+4)]

=(x+1)(x+4)(x-1)(x-2)/[(x+1)(x-2)(x-1)(x+4)]

=1.