若lx-y+3l与Ix+y_1999I互为相反数,求x+2y/x-y的值为多少?
3个回答
两个绝对值互为相反数说明这两个数都是0,接上面两个方程求解出x和y.
x-y+3=0
x+y-1999=0
解得x=998 y=1001
最后解出x+2y/x-y=1000
相关问题
若lx+6l与 l3y-2l互为相反数,求x+y的值
若Ix+6I与I3y-2I互为相反数,求x+y的值.
若|x-y+3|与|x+y-1999|互为相反数,求[x+2y/x−y]的值
若|x-y+3|与|x+y-1999|互为相反数,求[x+2y/x−y]的值
若|x-y+3|与|x+y-1999|互为相反数,求[x+2y/x−y]的值
若Ix+3I与I2y-3I互为相反数,求(x+y)除以(x-y)的直
|x-y+3|与|x+y—1999|互为相反数求x+y+3(x-y)的值
已知lx-3l与l2y一3l互为相反数,求x一y分之x十y的值
若lx一2l与(y+3)的2次方互为相反数,则x+y=___
若lx-7l与ly-2014l互为相反数球求x,y的值