3xy[2xy-3(xy-1/2x^2y)]

1个回答

3xy[2xy-3(xy-1/2x^2y)]
=3xy[2xy-3xy+3/2x^2y]
=3xy[-xy+3/2x^2y]
=-3x^2y^2+9/2x^3y^2

3x^2 y+{xy-[3x^2 y-(4xy^2 +1/2xy)]-(4x^2 y+3/2xy)}
3xy²-[xy-2(xy-3/2x²y)+3xy²]+3xy²,其中x=3,y
3x2y−[2xy2−2(xy−32x2y)+xy]+3xy2．
(3xy^2-2x^2)(1/3xy+2xy^3),其中x=-1,y=-2
化简求值3x²y-[2xy-2（xy-3/2x²y)+xy]+3xy²其中x=3、y=-1
（1）化简：3x2y-[2xy-（xy-[3/2]x2y+2xy）]
【xy(x²-3y)+3xy²】(-2xy)+x³y²(2x-y)
(5x²y-2xy²-3xy)-(2xy+5x²y-2xy²),x=-1/5,y
计算：（1）(√xy+2√y/x+√x/y+√1/xy)√xy （2）(√5-√3)^2-(√5+√3)^2
(3xy^2)^3乘[xy(2x-y)-2x(xy-y^2)].其中x=2 y=1/2