Question

设向量a=[cosa,(λ-1)sina],向量b=(cosβ,sinβ),(λ>0,0

Answer 1

1

由题意,(a+b)与(a-b)垂直,则,(a+b) dot (a-b)=|a|^2-|b|^2=0,即：|a|=|b|

而|b|=1,故,cosa^2+(λ-1)^2sina^2=1,即：(λ^2-2λ)sina^2=0,0