分解因式(x'2十x一6)(x'2十x一8)一24;(x十1)(x一2)(x一3)(x一6)十20;

2个回答

  • (x²+x-6)(x²+x-8)-24

    =(x²+x-6)[(x²+x-6)-2]-24

    =(x²+x-6)²-2(x²+x-6)-24

    =[(x²+x-6)-6][(x²+x-6)+4]

    =(x²+x-12)(x²+x-2)

    =(x-3)(x+4)(x-1)(x+2)

    (x+1)(x-2)(x-3)(x-6)+20

    =[(x+1)(x-6)][(x-2)(x-3)]+20

    =(x²-5x-6)(x²-5x+6)+20

    =(x²-5x)²-36+20

    =(x²-5x)²-16

    =(x²-5x+4)(x²-5x-4)

    =(x-1)(x-4)(x²-5x-4) (有理数范围内到此为止)

    =(x-1)(x-4)[x-(5+√41)/2][x-(5-√41)/2] (实数范围内)