Question

数字1,2,3,4,5,每个数仅用一次,用运算法则,得出999.

Answer 1

2*4*5^3-1=999

(2*5)^3-1^4=999

2*5^3*4-1=999

((4-2)*5)^3-1=999

4*2*5^3-1=999

(4/2*5)^3-1=999

(4*5/2)^3-1=999

4*5^3*2-1=999

(5*2)^3-1^4=999

(5/2*4)^3-1=999

5^3*2*4-1=999

5^3*4*2-1=999

(5*(4-2))^3-1=999

(5*4/2)^3-1=999