1+2+3...+n① n个数,求和 n(n+1)/2
2+3+4...n+1② 也是n个数,求和 n(2+n+1)/2
①+②=168
(n(n+1)+n(n+3))/2 =n(n+2)=168
n=12
3+5+7+…+(2n+1)有n项
3+5+7+…+(2n+1)= n(3+2n+1)/2=n(n+2)=168
n=12
1+2+3...+n① n个数,求和 n(n+1)/2
2+3+4...n+1② 也是n个数,求和 n(2+n+1)/2
①+②=168
(n(n+1)+n(n+3))/2 =n(n+2)=168
n=12
3+5+7+…+(2n+1)有n项
3+5+7+…+(2n+1)= n(3+2n+1)/2=n(n+2)=168
n=12