x=(-k)/(4+k²),y=4/(4+k²)
两式相除得:x/y=-k/4,k=-4x/y
将其带入y=4/(4+k²)得
y[4+(-4x/y)²]=4
4y+16x²/y=4(两边同乘以y/4)
y²+4x²=y
4x²+y²-y=0
答:化简得4x²+y²-y=0
x=(-k)/(4+k²),y=4/(4+k²)
两式相除得:x/y=-k/4,k=-4x/y
将其带入y=4/(4+k²)得
y[4+(-4x/y)²]=4
4y+16x²/y=4(两边同乘以y/4)
y²+4x²=y
4x²+y²-y=0
答:化简得4x²+y²-y=0