Question

如图,已知直线AB和CD相交于O点,∠COE=88°,OF平分∠AOE,∠COF＝32°,求∠BOD的度数.

Answer 1

∵∠COE＝88,∠COF＝32

∴∠EOF＝∠COE-∠COF＝88-32＝56

∵OF平分∠AOE

∴∠AOF＝∠EOF＝56

∴∠AOC＝∠AOF-∠COF＝56-32＝24

∵∠BOD与∠AOC为对顶角

∴∠BOD＝∠AOC＝24°

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