Question

1.某种型号的充电电池上标有“3.6V,1200mA*h”的字样,某额定功率为0.5W的小收音机使用一节此型号电池供电,

Answer 1

1）电池电能为 W＝1200mA*h*3.6V

收音机能使用时间 t=w/p=1200mA*h*3.6V/0.5w=8.64h

2)W=220V*0.09A*6h*15% = 64152J

3)W=Pt

P=W/t = 1.92kW*h/2d = 40 W

4)t=9W*20%*1h*80%/0.4W = 3.6 h