=a^(2n-1-2n-1)b^(3n-1-3n 2)c^2 =bc^2/a^2 27^2x÷9^x÷3^x=27 3^6x÷3^2x÷3^x=27 3^(6x-2x-x)=3^2 6x-2x-x=3
b^3n-1/a^2n-1×c÷b^3n-2/a^2n
1个回答
相关问题
-
计算:b^(3n-1)/a^(2n-1)×c÷b^(3n-2)/a^2n
-
b^3n-1 c^2/a^2n+1×a^2n-1/b^3n-2=
-
(b^3n-1×c^2/a^2n+1)×(a^2n-1/b^3n-2)等于多少
-
是否存在常数a,b,c使1×2^2+2×3^2+……+n(n+1)^2=n(n+b)(n+c)/a对一切n为自然数都成立
-
分式计算:(b^3n-1 )*c/(a^2n+1)除以 (b^3n-2)/(a^2n)
-
(3a^(n+2)b-2a^nb^(n-1)+3b^n)×5a^nb^n+3(n为正整数,n大于1)
-
(a-b)(a^(n-1)-b^(n-1))=(a-b)^2(a^(n-2)+a^(n-3)b+……+ab^(n-3)+
-
设三角形ABC的3条边长分别是a、b、c,切a=n×n-1,b=2n,c=n×n+1.
-
规定《a×n》=a÷n÷(n+1),如《1/3×2》=1/3÷2÷3=1/18.(1)求《5/6×9》的值.(2)《2/
-
已知n为大于1的自然数,计算b^3n-1c^3/a^2n+1 *a^2n/b^3n-2