解题思路:(1)(4)(5)(6)运用乘法分配律解答,
(2)按照从左到右顺序计算解答,
(3)运用加法交换律解答.
(1)2000÷[5/21]-3[1/5]×2000
=2000×([21/5]-3[1/5])
=2000×1
=2000;
(2)11[3/8]-4.13+3[2/5]
=7.245+3[2/5]
=10.645;
(3)4.87-1[5/13]+5.13
=4.87+5.13-1[5/13]
=10-1[5/13]
=8[8/13];
(4)6[7/15]×2.5-2[1/2]×4[7/15]
=(6[7/15]-4[7/15])×2.5
=2×2.5
x=5;
(5)5.9×0.7+0.59+0.02×59
=5.9×(0.7+0.1+0.2)
=5.9×1
=5.9;
(6)([1/13]-[1/18])×13×18
=[1/13]×13×18-[1/18]×13×18
=18-13
=5.
点评:
本题考点: 整数、分数、小数、百分数四则混合运算.
考点点评: (1)以及四则运算计算方法正确进行计算,(2)正确运用简便方法解决问题,是本题考查知识点.