Question

已知x²+y²+4x-6y+13＝0,x,y均为有理数,求x的y次方的值

Answer 1

x²+y²+4x-6y+13＝0

(x+2)^2+(y-3)^2=0

x+2=0,y-3=0

x=-2,y=3

x^y=(-2)^3=-8