(1)0.08mol (2)0.02mol 0.01mol
(1)消耗HCl的物质的量:0.2L×5mol/L-0.2L×4.6mol/L=0.08mol
(2)设Al、Fe的物质的量分别为x、y
27g/mol×x+56g/mol×y=1.1g
3x+2y=0.08mol
得 x=0.02mol y=0.01mol
(1)0.08mol (2)0.02mol 0.01mol
(1)消耗HCl的物质的量:0.2L×5mol/L-0.2L×4.6mol/L=0.08mol
(2)设Al、Fe的物质的量分别为x、y
27g/mol×x+56g/mol×y=1.1g
3x+2y=0.08mol
得 x=0.02mol y=0.01mol