Question

数字电路,公式法化为最简与或式,

Answer 1

Y1 = A'B'C + A'BC + ABC' + ABC

= A'C (B' + B) + AB (C' + C)

= A'C + AB

Y2 = ( (AB' + ABC)' + A (B + AB') )'

= ( (AB')' ( ABC)' + AB + AB' )'

= ( (A' + B) ( A' + B' + C') + A(B + B') )'

= ( A' + A'B' + A'C' + A'B + 0 + BC' + A )'

= ( A' (1 + B' + C' + B) + BC' + A )'

= ( A' + A + BC' )'

= 0