：¼xy²+（2x²y-1）-(½xy²+3/2x²y)
=¼xy²+2x²y-1-½xy²-3/2x²y
=-¼xy²+1/2x²y-1
=-¼×(-1)×4+1/2×1×2-1
=1+1-1
=1
化简求值：¼xy²+（2x²y-1）-(½xy²+3/2x²
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