因为｜y+5｜≥0,所以y+5=0,(5x+1)2=0
所以y=-5,x=-1/5
-3(2x-y)-｛7x-[6x+2y-(10x-8y)]-x-2(3x-4y)｝
=-6x+3y-7x+6x+2y-10x+8y+x+6x-8y
=3y-7x+2y-10x+x+6x
=5y-10x
=5*(-5)-10*(-1/5)
=-25+2
=-23
若｜y+5｜+(5x+1)2=0,求-3(2x-y)-｛7x-[6x+2y-(10x-8y)]-x-2(3x-4y)｝的
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