因式分解x^3-2x^2十x 已知x^2—4x十29-|oy+y^2=o,求x^2y^2+2x^3y^2+x^4y^2
1个回答
原式=x(x²-2x+1)
=x(x-1)²
(x²-4x+4)+(y²-10y+25)=0
(x-2)²+(y-5)²=0
x=2,y=5
原式=x²y²(x+1)²
=4*25*9
=900
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