Question

（1）2x^2-mx-m^2=0 （2）2x^2-(3m-n)x-2m^2+3mn-n^2=0

Answer 1

1）2x^2-mx-m^2=0

(2x+m)(x-m)=0

所以x1=-m/2,x2=m

（2）2x^2-(3m-n)x-2m^2+3mn-n^2=0

2x^2-(3m-n)x-（2m^2-3mn+n^2）=0

2x^2-(3m-n)x-(2m-n)(m-n)=0

[x-(2m-n)][2x+(m-n)]=0

所以x-(2m-n)=0,2x+(m-n)=0

所以x1=2m-n,x2=(n-m)/2