Question

当k取何值一元二次方程x平方－（2k-3）x+2k-4=0

Answer 1

x^2 - (2k-3)x + 2k-4 = 0

{x-(2k-4)}(x-1) = 0

x1=1,x2=2k-4

x1=1＜3

∴x2=2k-4＞3

2k＞7

k＞7/2