Question

计算[x²-x-2/x²-x-6]/[x²+x-6/x²+x-2]的结果是.

Answer 1

原式=[(x²-x-2)/(x²-x-6)]÷[(x²+x-6)/(x²+x-2)]

=[(x-2)(x+1)]/[(x-3)(x+2)] ÷[(x-2)(x+3)]/[(x-1)(x+2)]

=[(x-2)(x+1)]/[(x-3)(x+2)] ×[(x-1)(x+2)]/[(x-2)(x+3)]

=[(x+1)(x-1)]/[(x+3)(x-3)]