Question

好的加20分1,若多项式（m+2)x^(m-1)+4x+5是关于x的一次整式,m的值?2,已知(x-1)^x+2=1,整

Answer 1

(m+2)x^(m-1)+4x+5

m-1=1

m=2

(x-1)^(x+2)=1

x+2=0

x = -2

(-1/3)^(-3)×(-2/3)^0 + (-4/5)^(-1) × (-3/2)^(-3)

= (-3)^3 × 1 + (-5/4) × (-8/27)

= - 27 + 10/27

= - 26又17/27