(1)设A(x,y),则B(x,-y),C(-x,-y)
所以A,C关于原点对称
(2)1.AB,AC为腰:AB=5=AC,C1(-2,0),C2(8,0),C3(0,-4).
2.AB,BC为腰:BC=5,C4(-3,0),C5(0,9),C6(0,-1).
3.AC,BC为腰:算出AB:y=-3/4x+4,AB垂直平分线:y=3/4x+7/8
x=0,y=7/8; y=0,x=-6/7
C7(0,7/8),C8(-6/7,0)
(1)设A(x,y),则B(x,-y),C(-x,-y)
所以A,C关于原点对称
(2)1.AB,AC为腰:AB=5=AC,C1(-2,0),C2(8,0),C3(0,-4).
2.AB,BC为腰:BC=5,C4(-3,0),C5(0,9),C6(0,-1).
3.AC,BC为腰:算出AB:y=-3/4x+4,AB垂直平分线:y=3/4x+7/8
x=0,y=7/8; y=0,x=-6/7
C7(0,7/8),C8(-6/7,0)