x²+2mn-m²+n²
1个回答
x²+2mn-m²+n²
=(x+m)(x-m)+n(2m+n)
相关问题
解方程:(m²-mn-2n²)x²+(5m²+2mn-12n²)x+6
已知x=m²-2mn+n²,y=m²-2mn-n².当m=1,n=2时,求x-[
(m2-n2)x2+m2x+n2x+mn因式分解
mn-n=15,m-mn=6,则m-n=(),-2mn+m+n=()
已知m-n=4,mn=-1,求:(2mn+2m+3n)+(3mn+2n-2m)-(m+4n+mn)
急因式分解x^2-(m^2+n^2)x+mn(m^2-n^2)
mnx2-(m2+n2)x+mn=0(mn≠0)
1.已知m-n=2 mn=-2求(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值
已知m-n=5,mn=-3,求-(m+4n-mn)-(2mn-2m-3n)+(2n-2m-3mn)的值.