设A=X,则,EDA=X,BED=2X,又有ED=BD,BED=DBE=2X,而AC=AB,则C=ABC=(180-X)/2=90-X/2.
BD=BC,BDC=C=90-X/2.由三角形内角和:C+BDC+DBC=180,则180-X+90-X/2-2X=180,X=25.7°
设A=X,则,EDA=X,BED=2X,又有ED=BD,BED=DBE=2X,而AC=AB,则C=ABC=(180-X)/2=90-X/2.
BD=BC,BDC=C=90-X/2.由三角形内角和:C+BDC+DBC=180,则180-X+90-X/2-2X=180,X=25.7°