(Ⅰ)设甲、乙两人参加交通知识考试合格的事件分别为A、B
P(A)=
C 26
C 14 +
C 36
C 310 =
60+20
120 =
2
3 ,
P(B)=
C 28
C 12 +
C 38
C 310 =
56+56
120 =
14
15 .
∵事件A、B相互独立,
∴甲、乙两人考试均合格的概率为 P(A?B)=
2
3 ×
14
15 =
28
45 .
即甲、乙两人考试均合格的概率为
28
45 .
(Ⅱ)甲答对试题数ξ依题意知ξ=0,1,2,3,
p(ξ=0)=
C 34
C 310 =
1
30 ,
P(ξ=1)=
C 16
C 24
C 310 =
3
10 ,
P(ξ=2)=
C 26
C 14
C 310 =
1
2 ,
P(ξ=3)=
C 36
C 310 =
1
6 .
∴ξ的分布列如下:
∴甲答对试题数ξ的数学期望Eξ= 0×
1
30 +1×
3
10 +2×
1
2 +3×
1
6 =
9
5 .