3(a³-a²+1/2ab²)-1/2(6a³+4a²b+3ab&su
2个回答
3(a³-a²+1/2ab²)-1/2(6a³+4a²b+3ab²)
=3a³-3a²+3/2ab²-3a³-2a²b-3/2ab²
=-3a²-2a²b
=-a²(3+2b)
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