Question

题1：(2+1])[（2)2+1][（2)4+1][（2）8+1]+1=?题2：a-1/a=1 那么：(a)2+1/(a

Answer 1

(2+1)[（2)2+1][（2)4+1][（2）8+1]+1

=(2-1)(2+1)(2^2+1)(2^4+4)(2^8+1)+1

=(2^2-1)(2^2+1)(2^4+4)(2^8+1)+1

=(2^4-1)(2^4+4)(2^8+1)+1

=(2^8-1)(2^8+1)+1

=2^16-1+1

=2^16

a-1/a=1

两边平方

a^2-2*a*1/a+1/a^2=1

a^2-2+1/a^2=1

所以a^2+1/a^2=3