[x(x^2y^2-xy)-y(x^2-x^3y)]/(3x^2y)
={x[xy(xy-1)]-y[x²(1-xy)]}/(3x²y)
=[x²y(xy-1)-yx²(1-xy)]/(3x²y)
=[x²y(xy-1)+yx²(xy-1)]/(3x²y)
=[x²y(xy-1)+x²y(xy-1)]/(3x²y)
=[2x²y(xy-1)]/(3x²y)
=[2(xy-1)]/3
[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y
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