Question

已知函数f (x分之x+1)=x的平方分之x的平方+1+x分支1 求'f(x)

Answer 1

f[(x+1)/x]=(x^2+1)/x^2+(1/x)

f[1+(1/x)]=1+(1/x^2)+(1/x)=[(1+1/x)^2-(1/x)]=[(1+1/x)^2-(1+1/x)+1]

f(t)=[t^2-t+1]

f(x)=x^2-x+1