let lim(n->无穷)an= L
lim(n->无穷)an = lim(n->无穷)a(n+1)=L
lim(n->无穷)a(n+1)=lim(n->无穷) ((an+A/an)/2
你可以求出L
a1>0,an+1=((an+A/an)/2,求数列的极限
1个回答
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