f(x)=a(2x^2-3x-2)+2x+3
=a(2x=1)(x-2)+2x+3
g(x)=a(2x^2-3x-2)+4x-1
=a(2x=1)(x-2)+4x-1
a能整除
所以
只要算 (2x+3)/(2x+1)=1.2
(4x-1)/(2x+1)=2.-3
answer is 2-(-3)=5
f(x)=a(2x^2-3x-2)+2x+3
=a(2x=1)(x-2)+2x+3
g(x)=a(2x^2-3x-2)+4x-1
=a(2x=1)(x-2)+4x-1
a能整除
所以
只要算 (2x+3)/(2x+1)=1.2
(4x-1)/(2x+1)=2.-3
answer is 2-(-3)=5