计算[(x-1)/(x-2)-(x-2)(x-3)-(x-3)/(x-4)+(x-4)(x-5)]/(2x-7)
3个回答
原式=(38*x^2-116*x+110-4*x^3)/(x^2-6*x+8)
或原式=-2*(-19*x^2+58*x-55+2*x^3)/(x-2)/(x-4)
快啊
相关问题
x1 + x2 + x3 + x4 + x5 = 7 4x1 + 2x2 + 3x3 + 2x4 - 2x5 = 5 x
计算:(2x+3)(3x-4)>(x+1)(x-1)+5x(x+3)+7
X1 - X3 - X4 -5X5=0 X1+2X2+3X3+3X4+7X5=0 X1+X2+X3+X4+X5=0 X2
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