an-an-1=n-1
an-1-an-2=n-2
an=an-1+n-1=an-2+(n-1+n-2)=...=a1+(1+2+...+n-1)=n(n-1)/2+1
已知数列an满足an-an-1=n-1,且a1=1,则an=
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