2x^2+y^2+1=2xy-2x-根号下z-3
2x^2+y^2+1-2xy+2x+根号下z-3=0
(x-y)²+(x+1)²+根号下z-3=0
x-y=0 且x+1=0且z-3=0
解得 x= -1 ,y= -1,z=3
已知2x^2+y^2+1=2xy-2x-根号下z-3,求x、y、z的值
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