Question

已知方程5x的2m+n-3次幂+7y的m+3n-1次幂=2是二元一次方程.求m、n的值；

Answer 1

2m+n-3=1 ……①

m+3n-1=1 ……②

②×2-①得

5n =0

n =0

m = 2

∴原方程为：5x+7y=2

当x = y+1

5（y+1）+7y = 2

12y = - 3

y = -1/4

x= 3/4