Question

①（-4xy^3)*(-1/8xy)-(1/2xy^2)^2 ②-2(-a^2bc)^2*1/2a(bc)^3-(-ab

Answer 1

原式=1/2x^2y^4-1/4x^2y^4

=1/4x^2y^4

原式=-2(a^4b^2c^2)*1/2ab^3c^3+(abc)^5

=-a^5b^5c^5+a^5b^5c^5

=0