Question

(27-2x)(21-2x)=27x21x(1-1/4)解一元二次方程应用题. 要有过程的~~

Answer 1

(27-2x)(21-2x)=27x21x(1-1/4)

27x21-96x+4x^2=27x21x3/4

4x^2-96x+27x21x1/4=0

x^2-24x+27x21x1/16=0

x^2-24x+144-144+567/16=0

(x-12)^2-1373/16=0

(x-12-√1373/4)(x-12+√1373/4)=0

x=12+√1373/4或x=12-√1373/4