试说明代数式/-(3x²y+10x³)+3x³+6x³y+3x²y-(
1个回答
把括号去掉然后算最后得0
=-3x²y-10x³+3x³+6x³y+3x²y-6x³y+7x³
=-3x²y+3x²y+3x³+7x³-10x³+6x³y-6x³y
=0
相关问题
试说明代数式-(3x²y+10x³)+3x³6x³y+3x的值与x,y都无关
试说明代数式/-(3x²y+10x³)+3x³+6x³y+3x²y-(6x³y-7x³)的值与x,y都无关
是说明代数式-(3x2y+10x3)+3x3+6x3y+3x2y-(6x3y-7x3)的值与x,y都无关
试说明式子-(3x2y+10x3)+3x3+6x3y+3x2y-(6x3y-7x3)的值与x,y都无关.
试说明:无论x,y取值时,代数式(x^3+3x^2y-5xy^2-6y^3)+(y^3+2xy^2+x^2y-2x^3)
说明代数式-(3x平方y+10x立方)+3x立方+6x立方y+3x平方y-(6x立方y-7x立方)的值与x,y无关
试说明:多项式(5x³-7x³y+3x²y)+2x³-(-7x³y+3
试说明多项式(4x²-3x+1)+(4x²-3x+2y²)—(8x²—6x+2y
x+4y=6,x-3y=1,求代数式7y[x-3y]²-2[3y-x】²
2x-3y/3x+y=2,求代数式(4x-6y/9x+3y)+(18x+6y/4x-6y)的值