(x+2)/(x²-2x)-(x-1)/(x²-4x+4)
=(x+2)/[x(x-2)]-(x-1)/(x-2)²
=[(x+2)(x-2)-x(x-1)]/[x(x-2)²]
=(x²-4-x²+x)/[x(x-2)²]
=(x-4)/[x(x-2)²]
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(x+2)/(x²-2x)-(x-1)/(x²-4x+4)
=(x+2)/[x(x-2)]-(x-1)/(x-2)²
=[(x+2)(x-2)-x(x-1)]/[x(x-2)²]
=(x²-4-x²+x)/[x(x-2)²]
=(x-4)/[x(x-2)²]
很高兴为您解答,【学习宝典】团队为您答题.
请点击下面的【选为满意回答】按钮.