y=0代入方程 (2m²+m-3)x=4m-1
x=1,x=-1,分别代入得
m1=-1/2 m2=2
m3=(-5+sqrt(57))/4 m4=(-5-sqrt(57))/4
-(2m^2+m-3)/(m^2-m)=1
得m1=1,m2=-1;当m=1时,代入原式,不成立,所以m=-1
m1=-2/3 m2=1 m=1舍去
y=0代入方程 (2m²+m-3)x=4m-1
x=1,x=-1,分别代入得
m1=-1/2 m2=2
m3=(-5+sqrt(57))/4 m4=(-5-sqrt(57))/4
-(2m^2+m-3)/(m^2-m)=1
得m1=1,m2=-1;当m=1时,代入原式,不成立,所以m=-1
m1=-2/3 m2=1 m=1舍去