X+(X—1)+(X-2)+(X-3)+(X-4)=21
2个回答
X+(X—1)+(X-2)+(X-3)+(X-4)=21
5X-10=21
x=31/5
相关问题
1/(1x2x3)+1/(2x3x4)+1/(3x4x5)+.1/(20x21x22)=?
因式分解(1)x^3-11x²+31x-21 (2) x^3-2x²+4
求方程组的通解2X1-3X2+X3-5X4=1,-5X1-10X2-2X3+X4=-21,X1+4X2+3X3+2X4=
3(x-1)=x+21 x+4*5=2x-5*8
x=26,X^2-3x+4.21=?
(2X2)/1X3+(4X4)/(3X5)+(6X6)/(5X7)+...+(20X20)/(19X21)==?
解方程:4(x^2-7x+10)-(2x+3)(2x-1)=-21
x/8+x÷4/3=21 x÷3又1/3-1/5x=20 2/3x+x÷2/3=4/5
1X2X3+2X3X6十4X8X12十7X14X21/1X3X5十2X6X10十4X12X20十7X21X35的结果是什
先化简,再求值(3x+4x2−1+21−x)÷x+2x2−2x+1,其中x=4.