Question

求积分∫(secx/tan^2x)dx

Answer 1

∫[secx/(tanx)^2]dx

因为secx=1/cosx

所以∫[secx/(tanx)^2]dx

=∫[cosx/(sinx)^2]dx

=∫[1/(sinx)^2]d(sinx)

=-1/(sinx)

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