Question

【急】一道导数题 求y=sin∧2 cos(3x)的导数

Answer 1

y‘=[sin²(cos3x)]'

=2sin(cos3x) ×[sin(cos(3x))]'

=2sin(cos3x) cos(cos(3x)) (cos3x)'

=sin[2(cos3x)]×(-sin(3x)]×(3x)'

=-3sin3x × sin[2(cos3x)]