f(x)=1+sin2wx+(1+cos2wx) =根号2*sin(2wx+π/4)+2 T=2π/2W=2π/3 2W=3
f(x)=根号2*sin(3x+π/4)+2
g(x)=f(x-π/2)=根号2*sin[3(x-π/2)+π/4]+2=根号2*sin[3x-3π/2+π/4]+2
=根号2*sin[3x+3π/4]+2
-π/2+2kπ≤3x+3π/4≤π/2+2kπ
-5π/12+2kπ/3≤x≤-π/12+2kπ/3
单调增区间为：[-5π/12+2kπ ,π/12+2kπ/3]