Question

已知p(A）=0.4 p(B）=0.3,p(AUB)=0.6,求p(AB拔)

Answer 1

P(AB拔)=P(A拔∪B拔)=P(A拔)+P(B拔)-P(A拔B拔)

=1-P(A)+1-P(B)-P(A∪B拔)

=1-P(A)+1-P(B)-1+P(A∪B)

=1+P(A∪B)-P(A)-P(B)

=1+0.6-0.4-0.3

=0.9

汗啊,拔是B上的啊

P(AB)=P(A)+P(B)-P(A∪B)=0.4+0.3-0.6=0.1

P(AB拔)=P(A-B)=P(A)-P(AB)=0.4-0.1=0.3